Ideally the resistance of a
Voltmeter is infinite so that so that voltmeter does not alter circuit current.
A low resistance voltmeter may give correct reading when measuring voltage in
low resistance circuit but the Voltmeter produces unreliable and erroneous reading
when connected in high resistance circuit. This is because, as the resistance
of voltmeter is less when compared to the circuit resistance, this will act as
a shunt path for the current and therefore the voltage drop across the resistor
where we want to measure the voltage will be less. Because of this the reading
of voltmeter will not be the actual voltage drop rather it will be lower than
actually existed before the connection of the voltmeter.

*This effect is known as Loading Effect.*

Now, we will take an example
to better understand the Loading Effect. Consider the figure below.

It is desired to measure the
voltage cross the 50 kOhm resistor using two voltmeter A and B. Voltmeter A has a sensitivity of 1000 ohm/V
while for voltmeter B is 20,000 ohm/V. The range of both voltmeters are 0-50 V.

First of all we will
calculate the voltage drop across the 50 kOhm resistor.

Voltage drop across 50 kOhm
resistor = 50x150/(100+50)

= 50 V = True value

Means before the connection
of voltmeter the voltage drop across the 50 kOhm resistor is 50 V.

**Case1: When voltmeter A is used.**

Sensitivity of Voltmeter A =
1000 ohm/V

Therefore,

Resistance of Voltmeter R

_{VA}= SensitivityxVoltage
= 1000x50 = 50 kOhm

Now when this voltmeter A is
connected across the resistor of 50 kOhm, the equivalent resistance of the
parallel combination,

Req = 50x50 / (50+50)

=
25 Kohm

Hence, voltage across the
Req = 25x150 / (100+25)

= 30 V

Therefore we see that
voltmeter A reads much less than the true value. It should be noted that for
getting good accuracy, the resistance of voltmeter >>> circuit
resistance but here in this case both are equal.

**Case2**:

**When voltmeter B is used.**

Sensitivity of Voltmeter A =
20,000 ohm/V

Therefore,

Resistance of Voltmeter R

_{VA}= SensitivityxVoltage
= 20,000x50 = 1000 kOhm

Mind here that the
resistance of voltmeter >>> circuit resistance i.e 1000 kOhm
>>>>50 kOhm so definitely we are going to get voltage reading close
to true value i.e 50 V.

Now when this voltmeter A is
connected across the resistor of 50 kOhm, the equivalent resistance of the
parallel combination,

Req = 50x1000 / (50+1000)

=
47.6 Kohm

Hence, voltage across the
Req = 47.6x150 / (100+47.6)

= 48.37 V

See how close to the true
reading we get. So in second case loading effect is not prominent as the voltmeter
resistance is much higher than the circuit resistance but in first case loading
effect id dominating as the voltmeter resistance is comparable to circuit
resistance.

*It should also be noted that meter with higher sensitivity gives reliable result. This is particularly true where voltage measurement is done in higher resistance circuit.*
Thank you!

## 1 comment:

Enter your comment...

I find it helpful.please send me the password...kengajones93@gmail.com

Post a Comment